How long does one complete cycle of a 60 Hz waveform take?
Answer in ms.
Show the answer
16.67 ms
Period T = 1 ÷ f = 1 ÷ 60 = 0.01667 s. 0.01667 s × 1,000 = 16.67 ms.
Reference: AC fundamentals: period T = 1 ÷ f
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30 questions from the electrical theory and calculations practice test.
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How long does one complete cycle of a 60 Hz waveform take?
Answer in ms.
16.67 ms
Period T = 1 ÷ f = 1 ÷ 60 = 0.01667 s. 0.01667 s × 1,000 = 16.67 ms.
Reference: AC fundamentals: period T = 1 ÷ f
What is the peak voltage of a 120 V RMS sine wave? (Use 1.414.)
Answer in V.
169.7 V
E peak = E rms × 1.414 = 120 × 1.414 = 169.7 V.
Reference: AC fundamentals: E peak = 1.414 × E rms
A sine wave has a peak value of 340 V. What is its RMS (effective) value?
C. 240 V
E rms = E peak × 0.707 = 340 × 0.707 = 240.4 V, about 240 V. 217 V uses 0.637, which gives the average value rather than the RMS value, and 481 V multiplies by 1.414 when it should divide.
Reference: AC fundamentals: E rms = 0.707 × E peak